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| - Why does a low-pressure wire-discharge exist self-sustained?
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| - Numerical study of a self-sustained low-pressure (6.8 $un{Pa}$ or 50 $un{mTorr}$) wire discharge in helium is reported. The current-independent voltage drop across the cathode sheath is found to be of ~250 $un{V}$. The other part of the discharge voltage is essentially applied across the anode sheath. It drains electrons from the quasi-neutral plasma and thus presents a necessary condition for discharge maintenance. Two major groups of electrons have been distinguished: the fast electrons of ~(24-250) $un{eV}$, as well as a very small fraction of hot (run-away) electrons with the energy close to the discharge voltage, are responsible for gas ionization throughout negative glow while the thermalized electrons of ~1's eV are easily captured by the anode and so removed from the discharge.
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