| Abstract
| - The fact that f11(1)(Θ) and p11 are equal was overlooked in the first section of the above paper. Equation (1.1) should readL(θ)∝{p11(θ)}N1-N2∏t=2k{f11(t)(θ)}α′t-1{M(θ)}δ0,xy,whereM(θ)=1-∑t=1r+1f11(t)(θ),r is the number of 0's in the last run if the sequence ends with 0's, k is the maximum run length of 0's observed plus one, excluding the last run if the sequence ends with 0's, and δ0,xy is one or zero depending upon whether the last, that is the Nth, observation is zero or one respectively. Similar changes can easily be made in equations (2.1), …, (2.6), and therefore, after corresponding changes in E2(O), the oorrect entries for the second row of Table 1 are: E2(Θ) 0·9693 0·8580 0·7021 0·5259 0·3428 0·1717 0·0646 0·0143 0·0O13 My thanks are due to Mr 0. A. Raissi-Ardali for making various corrections.
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